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      Faraday's Law of Electrolysis

As an example, if a given amount of electricity releases 5 g of H2 gas when passed through an electrolysis cell for the decomposition of water, then twice as much electricity will produce 10 g of hydrogen gas.

Furthermore, if enough electricity is passed through the cell to yield 2 g of H2 gas at the cathode, then 16 g of O2 gas will be released at the anode. These numbers are easily recognizable as representing 1 mole of H2 and 1/2 mole of O2, which are the relative proportions in which these gases combine to form H20. In Faraday's time, his experiments were a remarkable set of observations that helped to establish the principles of chemical combination. Today they are self-evident consequences of the theory that electrons form chemical bonds.

We have referred to Faraday's constant previously as representing one mole of electrons, and have used it in the form

F = 23.056 kcal mol-1 eV-1

It is more convenient in electrolysis experiments to express F in coulombs, the customary unit of electrical charge.The charge on an electron is 1.6021 x 10-19 coulomb, so one mole of electrons will have a total charge of

1.6021 x 10-19 coulomb x 6.022 x 1023 mol-1 =

96,487 coulombs mol-l

Passing 96,487 coulombs of electricity through a cell means sending one mole of electrons from one electrode to the other, with the corresponding chemical changes.

 

 

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