The most commonly encountered oxidation states for the nonmetals
are shown in the table below, along with examples.
The highest possible positive oxidation state of an atom is the
charge that it would have if it lost all of the electrons in its
outer, incomplete electron shell.
Thus carbon and silicon have maximum oxidation numbers of +4 because
they both have four electrons to lose. Nitrogen and phosphorus have
a maximum ON of +5, as in HNO3and
H3PO4.
Sulfur has a maximum of +6, as in H2SO4.
You might expect oxygen to behave the same way, but oxygen is too
small and holds its outer electrons too tightly. (Compare the first
ionization energies of O and S on Page 9.)
No oxygen compounds are known in which oxygen has an ON as high
as +6. The size effect seen with oxygen applies even more strongly
to fluorine.
Chlorine in HClO4 shows an ON of
+7, the expected maximum; but the smaller fluorine atom holds its
electrons very tightly and has no compounds with positive oxidation
states
|
|
The lowest possible negative oxidation state of an atom is the
charge that the ion would have if it picked up enough electrons
to fill its outer shell completely and produce the electronic configuration
of the next heavier noble gas.
For F and Cl, this means a minimum ON of -1 as in HF and HCl; for
O and S, -2 as in H20 and H2S;
for N and P, -3 as in NH3and PH3;
and for C and Si, -4 as in CH4and
SiH4.
The two extreme maximum and minimum values, plus ON = 0, are the
most common oxidation states for the elements we have discussed
so far.
Intermediate states are less common and usually occur at intervals
of two in ON, representing shifts of pairs of electrons.
Thus sulfur has common oxidation states of -2, 0, +4, and +6; and
chlorine shows states -1, 0, +1, +3, +5, and +7. Though others to
these are possible. For example, ClO2,
where chlorine has an oxidation state of +4 can be formed, but is
not common.
|